The arc length shown in blue is 15 feet.
diagram is in link, click on it or copy and paste it into browser:
Part I: State the equation that relates arc length to central angle.
Part II: Find the angle in radians.
Part III: Convert your answer to degrees and write it to the nearest hundredth of a degree.
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OpenStudy (anonymous):
OpenStudy (chosenmatt):
what did you come up with?
OpenStudy (anonymous):
I think the equation is arc lenght=r*theta @chosenmatt
OpenStudy (chosenmatt):
good job!!
OpenStudy (anonymous):
but I need help figuring out the values
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OpenStudy (anonymous):
@chosenmatt
OpenStudy (perl):
need help?
OpenStudy (anonymous):
@perl yes please
OpenStudy (perl):
arclength = radius * theta, where theta is central angle in radians
OpenStudy (anonymous):
can you help me to find the values?
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OpenStudy (anonymous):
I'll do the rest
OpenStudy (perl):
ok
OpenStudy (perl):
we are given that arclength of the unshaded arc is 15 feet
OpenStudy (anonymous):
yeah
OpenStudy (perl):
we know the radius is 6
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
wait isn't 3?
OpenStudy (anonymous):
@perl
OpenStudy (perl):
the radius is 6
OpenStudy (anonymous):
@perl how do you know?
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OpenStudy (perl):
I looked at the graph
OpenStudy (anonymous):
Ok
OpenStudy (perl):
do you see how the circle cuts x = 6
OpenStudy (perl):
intersects (6,0) and (0,6)
OpenStudy (anonymous):
@perl it's 3 actually cuz the diameter is 6 and the raidus is half the diameters so it is equal to 3
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OpenStudy (perl):
no the diameter is 12
OpenStudy (anonymous):
how is 12 dude? it's 6
OpenStudy (perl):
radius is half the diameter , radius is 6
OpenStudy (perl):
my draw button has died, but
OpenStudy (anonymous):
the diameter is 6
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