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find x
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\[200<3x ^{3}<400\]
i dont want the answer i want the method
start by dividing 3 thourgh out
?
\[200<3x ^{3}<400\] divide 3 though out : \[\dfrac{200}{3}<\dfrac{3x^{3}}{3}<\dfrac{400}{3}\]
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\[\dfrac{200}{3}<x^3<\dfrac{400}{3}\]
next take cuberoot through out
\[ \sqrt[3]{\dfrac{200}{3}}<\sqrt[3]{x^3}<\sqrt[3]{\dfrac{400}{3}}\]
\[ \sqrt[3]{\dfrac{200}{3}}<x <\sqrt[3]{\dfrac{400}{3}}\]
those are the range of values for x ^
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thankyou so much (:
yw:)
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