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when five people join i post answer
hellooooooooo were is the question
5(-3x - 2) - (x - 3) = -4(4x + 5) + 13
find "x"
@1568
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i don't know what its called but -7=-7
Nope!
@1497
\[5(-3x-2)-(x-3)=-4(4x+5)=13;\] \[-15x-10-x+3=-16x-20+13.\]
The whole thing cancels out. You get zero equals zero; you cannot solve this equality for a given value of x, because combining like terms just results in\[0=0.\]
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Isnt x all numbers?
You win!
(Who, lol.)
who wins
Marie is also entirely right, what she said is true, too. x can be any value at all. It's a trivial solution, but it's still entirely true.
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Yup
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