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OpenStudy (anonymous):
2KClO3-->2KCl + 3O2 What mas of O2 can be produced by letting 12.00 moles of KCLO3 react?
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OpenStudy (anonymous):
(12.00mol KCLO3) X (3mol O2/2mol KCLO3) X (32g O2/ 1mol O2) =576g O2
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