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Chemistry 9 Online
OpenStudy (anonymous):

2KClO3-->2KCl + 3O2 What mas of O2 can be produced by letting 12.00 moles of KCLO3 react?

OpenStudy (anonymous):

(12.00mol KCLO3) X (3mol O2/2mol KCLO3) X (32g O2/ 1mol O2) =576g O2

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