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i just need the number on the last part its not 4x
\[\cosh x - \sinh x = \dfrac{e^x+e^{-x}}{2} - \dfrac{e^x-e^{-x}}{2} = e^{-x}\]
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yes...
i know that:) wouuuu
your function is same as \[y = 7 e^{-2x}\]
oh man like that? not like y=7e-2x
so it's in exponential form? this is my last try is it 100% right?
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do not rush, thats not your answer
thats your function you need to find the tangent line to that function at the given point (0, 7)
oh okay no wonder i was confused
are you still confused ?
thats where i go wrong
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idk i have 4x idk why?
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