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Given that 2pi=theta=3pi, determine the value of arccos(cos(theta)). I know the answer is theta-2pi, but have no idea how and I have a final coming up soon. Please help.
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you have to go back around the circle again to get between \(0\) and \(\pi\)
Ok so im still kinda confused, could you show that visually somehow? @satellite73
or nah @satellite73
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