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how would I solve 3^x^3 = 9^x
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\[3^{x ^{3}} = 9^{x}\]
you mean this?
Yes
well \( \Large 9^{x} = 3 ^{2x}\) so \( \Large 3^{x ^{3}} = 3 ^{2x}\) so you can say 2x = x^3
I'm sorry but I don't understand
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as 9 = 3^2 so 9^x is (3^2)^x = 3 ^ 2x and it's equal to 3^x^3 so 3^x^3 = 3^2x
got it?
I think so
nice ;)
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