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Differential Equations
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find the equation of the normal to y=xsquare-4 which is parallel to x+3y-1=0
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so you know how to find the equation for the slope of a tangent line?
we can start there.
Normal to a curve is a line that is perpendicular to the line that is tangent to the curve.
The derivative is the general slope of a tangent to a curve. The normal then is the negative reciprocal of the derivative (because given the slope of a line, the negative reciprocal of the slope is the slope of a line perpendicular to it).
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