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y=4csc2(x-pi/2)
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do you have a calculator at hand?
and what is the question?
just a sec
do you know to what value equals csc2(x-pi/2)
are u graphing this?
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cscx=1/sinx---------->csc2x=1/sin2x
sin2x=2sinx*cosx
oh you wanted to solve for x
\[\csc2(x-\pi/2)=1/(\sin2(x-\pi/2)\]
you can look at it using introspection and see that it is phase shifted -pi/2, so pi/2 to the right, so at y=0; x=pi/2
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