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Mathematics 10 Online
OpenStudy (anonymous):

Solve lnx=−2 for x

OpenStudy (loser66):

Where are you stuck?

OpenStudy (anonymous):

not sure how to begin this

OpenStudy (loser66):

\[log_a b =c \rightarrow a^c=b\] ln is just a = e , you can write it as \(log_e x=-2\), then x =??

OpenStudy (anonymous):

e^-2?

OpenStudy (loser66):

yup

OpenStudy (anonymous):

or 1/e^2

OpenStudy (loser66):

yup again:)

OpenStudy (anonymous):

okay thank you. that was pretty easy.

OpenStudy (loser66):

hihihi... glad to hear the sentence "that was pretty easy."

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