Question

A pair of corresponding sides of two similar pentagons have lengths of 12 cm and 28 cm. What is the ratio of the areas of the two pentagons?

Answer 1

12/28
27/343
28/12
9/49

Answer 2

the ratio of their areas = 12^2 / 28^2

Answer 3

or 144/784
if you factor these numbers you can simplify to get one of your options

Answer 4

Area of a regular is (S^2)*n/4*tan(180/n)
put n=5 and for pentagon 1, S=12 and another one will be S=28.
Divide them and get answer.
Consult further if any problem is coming