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Linear Algebra
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which equation is the equation of a line that passes through (-10 3) and is perpendicular to y=5x-7
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Well, for a line to be perpendicular, it just needs to have it's slope be the negative inverse. That is to say \(-1/5\) will be the slope in this case.
So we end up with: \[ \frac{y-(3)}{x-(-10)} = -\frac 15 \]And we just have to solve for \(y\) if we want it in slope point formula.
Refer to the attached plot.
Thank you! :D
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