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simplify: (2m^3n^2)^5 a)10m^8n^7 b)10m^15n^10 c)32m^8n^7 d)32m^15n^10
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Distribute the 5 over all the terms, what do you get?
\[\huge (2m^3n^2)^5 \implies (2^5m^{3 \times 5}n^{2 \times 5})\]
a
simplify : (3x)^2*x^-1 a)3x b)9/x^2 c)9x d)3/x^2
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