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Assume the domain of f and f^-1 is (-infinity,infinity). Solve the equation for t: f((1-2t)/(1+2t)) = 7 ; f^-1 (7) =-3
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\[ f^{-1}(f(x)) =x \]
Let \[ x=\frac{1-2t}{1+2t} \]
\[ f(x) = 7 \]take \(f^{-1}\) of both sides and get: \[ x = f^{-1}(7) = -3 \]
And so \[ x=-3\implies \frac{1-2t}{1+2t} = -3 \]
Can you solve for \(t\) now?
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