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Trigonometry
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Can anyone can prove this..
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\[\cos 3\theta= 4\sin ^{3}\theta -3\cos \theta \]
@iGreen
@perl
let t = theta cos(2t + t ) = cos(2t)cost - sin(t)sin(2t)
that formula is incorrect, above
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plug in theta = 0 cos (3*0) != 4 sin(0)^3 - 3 cos(0) 1 != 4*0 - 3*1
ok
so you're done :) you have a counterexample, and it is a false statement generally
oh! is that it :D ?
you cant prove a false statement unless theres a typo
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