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Trigonometry 13 Online
OpenStudy (anonymous):

Can anyone can prove this..

OpenStudy (anonymous):

\[\cos 3\theta= 4\sin ^{3}\theta -3\cos \theta \]

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

@perl

OpenStudy (perl):

let t = theta cos(2t + t ) = cos(2t)cost - sin(t)sin(2t)

OpenStudy (perl):

that formula is incorrect, above

OpenStudy (perl):

plug in theta = 0 cos (3*0) != 4 sin(0)^3 - 3 cos(0) 1 != 4*0 - 3*1

OpenStudy (anonymous):

ok

OpenStudy (perl):

so you're done :) you have a counterexample, and it is a false statement generally

OpenStudy (anonymous):

oh! is that it :D ?

OpenStudy (perl):

you cant prove a false statement unless theres a typo

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