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what are the real or imaginary solutions of the polynomial equation125x^3+343=0
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might want to consider this as a cubic sum formula
sum of cubics that is
Take 343 to the LHS, then divide both sides by 125. What we get is x^3 = -343/125
We take the cube root of the LHS, and replace root -1 as i. (so as to get imaginary root)
7^3=343
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