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Mathematics 21 Online
OpenStudy (anonymous):

plz help

OpenStudy (anonymous):

OpenStudy (campbell_st):

start by solving for x AD has a length of 2x + 20 but you are told AD = 40 so 2x + 20 = 40 then x = 10 now triangles ABG abd ACF are similar by angle angle postulate so using the ratio of corresponding sides AB = 10 and AC = x + x + 10 or 30 then \[\frac{BG}{39} = \frac{10}{30}\] solve for BG

OpenStudy (anonymous):

is it 13

OpenStudy (campbell_st):

that would be my answer

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so what is the perimeeter

OpenStudy (campbell_st):

well you know the value of x... so that should make it easy...

OpenStudy (anonymous):

can u tell me

OpenStudy (campbell_st):

no.... the last part is uses the ratio of corresponding sides in similar triangles.

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