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start by solving for x AD has a length of 2x + 20 but you are told AD = 40 so 2x + 20 = 40 then x = 10 now triangles ABG abd ACF are similar by angle angle postulate so using the ratio of corresponding sides AB = 10 and AC = x + x + 10 or 30 then \[\frac{BG}{39} = \frac{10}{30}\] solve for BG
is it 13
that would be my answer
ok
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so what is the perimeeter
well you know the value of x... so that should make it easy...
can u tell me
no.... the last part is uses the ratio of corresponding sides in similar triangles.
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