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@DanJS
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cN you check my answer? i got 2pi
@DanJS
16/3
pi/2=1.57 3.14 6.28 12.56
@DanJS
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um
ok so f(x) = y = sqrt(4-x^2)
equation of a circle y^2 + x^2 = 2^2
Centered at the origin and radius 2
and you want the area from 0 to 2
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|dw:1418523809323:dw|
area of a circle is pi*radius ^2 so half is (1/2)pi*2^2 = 2pi
yeah 2 pi is correct
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