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What is the range of the exponential -(1/3)^x-2 ?
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Which do you mean?\[f(x) = -(1/3)^{x-2}\]or\[f(x) = -(1/3)^x-2\]
the first one
when x is negative and large in magnitude say negative infinity \[f(-\infty) \to -(1/3)^{-\infty-2}\to -(1/3)^{-\infty}\to-(3)^\infty \to -\infty\]
when x is large and positive \[f(\infty)\to-(1/3)^{\infty-2}\to-(1/3)^\infty\to\]
what does the function trend toward for a large positive input?
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0
good, also \[f(0)=-(1/3)^{0-2}=-(1/3)^0=-1\] so the function gives values between negative infinity and zero
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