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What is the 9th term of this geometric sequence? 2/3, 2, 6, 18, 54, 162, ...
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each is 3 times the last
2/3 * 3^(n-1)
let n = 9 for the 9th term
4374
\[a _{n} = \frac{ 2 }{ 3 } * 3^{n - 1}\]
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is my answer right ?
i didnt calculate. lol hold on
yea
ok (:
thank you ! your such a big help
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you can test by putting in a known value, like n = 4th term and see if it comes out to 18
(2/3) *3^(4-1)
true
so now you can find the 1,876,985th term!
haha thank you !
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