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What is 3^9x when 27^x=4 And solve for (2^x)3x+3x=1 (two different questions^)
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\[27^x=4\] so \[3^{3x}=4\]
but the bases are not the same :(
they are now
\[27=3^3\]so \[27^x=3^{3x}\]
No, i mean 3 is not the same with 4
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since \[3^{3x}=4\] you can compute \[3^{9x}=(3^{3x})^3\]
Yeah, but what about 4?
the 4 is what you are going to cube
\[3^{9x}=(3^{3x})^3=4^3\]
What happens next?
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cube 4
Why?
nvm
okok
@satellite73 ?
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