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OpenStudy (anonymous):
what is the position vs time graph for the given force vs time graph? (pictures attached) plzz help :D
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OpenStudy (anonymous):
@hartnn
OpenStudy (anonymous):
any ideas? haha
OpenStudy (anonymous):
@surry99
OpenStudy (surry99):
no image is coming up for me to see
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OpenStudy (surry99):
ok i see it now.
OpenStudy (surry99):
ok so force vs time is constant and the force is negative...agreed?
OpenStudy (anonymous):
yes
OpenStudy (surry99):
ok so is the force is negative and constant what does that tell you about acceleration?
OpenStudy (anonymous):
acceleration is zero?
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OpenStudy (surry99):
no...try again...F=ma and force is negative and constant
OpenStudy (anonymous):
acceleration is negative as well then? idk lol
OpenStudy (surry99):
yes acceleration is negative....good.
so if the acceleration on an object is negative is it speeding up of slowing down?
OpenStudy (anonymous):
slowing down
OpenStudy (surry99):
good...now you need to look for a kinematic equation that relates position. time and acceleration.
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OpenStudy (anonymous):
d=1/2 at^2+(vi)t?
OpenStudy (surry99):
sure that will work...now assume the acceleration is some negative number.
If you started graphing d vs t starting at t = 0, what shape would you get?
OpenStudy (anonymous):
would it be like a parabola
OpenStudy (anonymous):
oh wait thats not right
OpenStudy (surry99):
yes parabola is correct but would it open up or down.
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OpenStudy (anonymous):
oh open down
OpenStudy (anonymous):
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