Question

how do i solve this 5cosθ -2sinθ =2

Answer 1

you can replace the sin (or cos) using sin^2 + cos^2 = 1

Answer 2

you can't divide since cos(theta) could be zero!

Answer 3

you can do \(25\cos^2\theta+4\sin^2\theta-20\sin\theta\cos\theta=4\)
\(21\cos^2\theta-20\sin\theta\cos\theta=0\)
take if from there

Answer 4

of course i used cos^2+sin^2=1
an simplified