Question

2k2 + 6k + 180 = (k - 6)(k + __). To complete this equation is 12? Need help please

Answer 1

\[2k^2 + 6k + 180 = (k - 6)(k + ?)\]
Find the roots of \[2k^2 + 6k + 180 = 0 \]

Answer 2

so still need help

Answer 3

\[2k^2 + 6k + 180 = (k - 6)(k + a)\]
\[2k^2 + 6k + 180 = (k^2 - 6k + ak + 6a)\]
you can solve by this method

Answer 4

method ok but that should be a -6a at the end not +6a

Answer 5

that is what its showing that I posted :(

Answer 6

I meant what was just above my post

Answer 7

im coming up with false but wanna make sure that its not 12 to finish the equation

Answer 8

(k-6)(k + a) the last entry when expanded (-6)*(+a) = - 6a

Answer 9

ok thankyou so much :)

Answer 10

I don't have a -6a:(

Answer 11

36
-5
9
-9
these are the answers