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MIT 18.01 Single Variable Calculus (OCW)
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solve x + ln x + e^x=0
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you can solve it graphically or you can use Newton's method: 1) guess an answer (say x = 1) 2) update x by x := x - f(x) / (df/dx) 3) if f(x) is not small enough (say 10^-6) return to 2 x f(x) df/dx new x 1.000000 3.718282 4.718282 0.211942 0.211942 -0.103428 6.954357 0.226814 0.226814 -0.002215 6.663497 0.227146 0.227146 -0.000001 6.657462 0.227146 answer = 0.227146
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