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Trigonometry
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OpenStudy (anonymous):
Can I have someone review my trigonometry work?
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OpenStudy (anonymous):
The question is Simplify the trigonometric expression. Show your work. the equation is 1/1+sin theta + 1/ 1-sin theta. So I did 1-sin theta/(1+sin theta) (1-sin theta) + 1+sin theta/ (1+sin theta) (1-sin theta) = 1-sin theta + 1+sin theta/(1+sin theta) (1-sin theta) = 2/1 - sin^2 theta= 2/cos^2 theta = 2sec^2 theta. So 2sec^2 theta is the answer
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