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rewrite with only sin x and cos x. cos 3x
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you can rewrite it: \(\cos(3x) = \cos(2x+x)\)
then you use sum formula
yeah, i got it to cos\[\cos 2x(\cos x- \sin 2x \sin x)\]
now do same with cos 2x and sin 2x: \(\cos (2x) = \cos(x+x)\)
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