FAN AND MEDAL AND TESTIMONIAL!! art A: Explain why the x-coordinates of the points where the graphs of the equations y = 8x and y = 2x + 2 intersect are the solutions of the equation 8x = 2x + 2. (4 points) Part B Make tables to find the solution to 8x = 2x + 2. Take the integer values of x between -3 and 3. (4 points) Part C: How can you solve the equation 8x = 2x + 2 graphically? (2 points)
@AlexandervonHumboldt2
all x's are exponents...
is part A because they both are y=something so you can equate them together?
solve equation => y=8x and y=2x +2 which gives x= 1/3... which satisfies the equation 8x = 2x +2
hence the solution
@camerondoherty @dan815
i think u can make the table urself
dan please say you can help explain part A?
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@satellite73
they arent linear they are exponents.
ohk den
no problem process still remains the same
i need part A: not the answer
ohk
@dan815 help me please.
because at that point is where the x,y values of both eqations are the same
so that x value when input into both equations yieds the same y
well idk part a
when u equate the two equations => u get this 8^x = 2^x +2 which is same as the equation that u r given ... that is 8^x = 2^x +2 this. hence solution of the curve satisfies the equation @knightmare6
DUDE I DONT GET WHAT YOU MEAN I JUST NEED PART A TO CONTINUE
dan. can you please explain
@dan815
that is part A @knightmare6
okay now to part B thanks
that cant be because it says something about the x cordinate.
graph 1 => y = 8^x graph 2 => y = 2^x +2 plug in different x's between -3 and 3 .... and find different y's corresponding to those x's... when the y's become equal ... it will be the required solution .... that x is the solution.
i got part A.
@knightmare6 @ part b
i did part B
okay i finished all of it thanks for trying to help me out i just got confused.
:)
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