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cos(theta) <0
sin(theta) is the y value on a unit circle, the tangent is the y/x value on a unit circle (x,y) = (cos(theta), sin(theta))
and tan(theta) = y/x is negative
huh
what quadrant does that leave you in?
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sorry, sin(theat) is the y value, and is positive, and cos(theta) the x value is negative neg x value and pos y value
leaves you in the second quadrant, so between theta = 90 and theta = 180
\[-Tan(\theta) = \frac{ \sin(\theta) }{ -\cos(\theta) } = \frac{ + }{ - }\]
where (x,y) = (cos, sin) you have (-x,+y) ....second quadrant
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