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MIT OCW Physics
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OpenStudy (anonymous):
How much work is required to accelerate a 0.145 kg baseball from rest, to a speed of 38.7 m/s?
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OpenStudy (anonymous):
Work done by external force is equal to change in kinetic energy, in this case 1/2mv^2
OpenStudy (anonymous):
you would use W = KE = 1/2mv^2
OpenStudy (anonymous):
What @ANANYANAYAK said haha
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