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Simplifysquare root of 2 multiplied by the cube root of 2.
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2 to the power of 1 over 6 2 to the power of 2 over 3 2 to the power of 5 over 6 2 to the power of 7 over 6
sqrt2=(6root) of 8 cuberoot 2=(6root) 4 (6root 8)*(6root 4)=(6root)(8*4)=(6root)(32)
so the answer is what
(6root)32
\[\sqrt[6]{32}\]
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when i did that i got 33.9
\[\sqrt{2}\sqrt[3]{2}=2^{\frac{1}{2}}2^{\frac{1}{3}}=2^{\frac{1}{2}+\frac{1}{3}}=2^{\frac{3}{6}+\frac{2}{6}}=2^{\frac{5}{6}}\]
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