Question

Solve for x.

-ax + 3b > 5

x > the quantity 3 times b minus 5 all over negative a
x > the quantity 5 minus 3 times b all over negative a
x < the quantity 3 times b plus 5 all over negative a
x < the quantity negative 3 times b plus 5 all over negative a @Mertsj

Answer 1

@camerondoherty

Answer 2

1. Subtract 3b from both sides.
2. Divide both sides by -a
3. Don't forget to flip the inequality symbol when dividing by a negative