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Please help! I need to pass this. I don't understand it at all. :( how many solutions does the equation have 3(4x-2)=2(6x-3) A. one solution B. no solution C. infinite solutions
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\[3(4x-2)=2(6x-3) \] lets solve it multiply out, what do you get?
aka use the distributive property on the left and the right
if you are not sure how to do it, say so and i will show you
12? i'm not too sure, sorry!
you get a \(12\) all right lets go slow
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\[a(b+c)=a\times b+a\times c\] so \[3(4x-2)=3\times 4x+3\times (-2)\] or more simply \[3(4x-2)=12x-6\]
now we do the same thing on the other side of the equal sign
ohhh that makes sense.
what do you get when you do it on the right? we are not done yet
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