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Mathematics 9 Online
OpenStudy (anonymous):

what is the equation of the parabola in vertex form x^2+6x-y+3=0

OpenStudy (anonymous):

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

I got C?

OpenStudy (anonymous):

yes its C

OpenStudy (anonymous):

x^2+6x-y+3=0 x^2+6x+9-y+3-9=0 where i added +9 and -9 note: x^2+6x+9=(x+3)^2 so final answer is (x+3)^2-y-6=0 --> (x+3)^2=y+6

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