LOG3 (X-24) + LOG3 (X) = 4
I'm trying to solve the LOG problem above the I have 2 LOG problems I'm having difficulty with. With this one I have gotten down to 0= X^2 - 24X -81 but cant factor it, not sure if I've done it correctly :/ cuz I cant factor it

Question

LOG3 (X-24) + LOG3 (X) = 4
I'm trying to solve the LOG problem above the I have 2 LOG problems I'm having difficulty with. With this one I have gotten down to 0= X^2 - 24X -81 but cant factor it, not sure if I've done it correctly :/ cuz I cant factor it

jhannybean · Answer

Remember: $\log(a) + \log(b)=\log(ab)$

jhannybean · Answer

$$a=(x-24) ~ , ~ b=x$$

anonymous · Answer

Yes, what I have so far is LOG2 X(X-24)=4 
then LOG3 (X^2 -24X) =4
3^4 = X^2 -24X
0 = X^2 -24X - 81

anonymous · Answer

I think the next step is to factor it but I cant so I'm guessing I did something wrong

jhannybean · Answer

Alright, let me work it out, checking.

jhannybean · Answer

Ok, think of factors that will multiply to give you -81 but add to give you -24

hint: 3 is one of them

anonymous · Answer

O! +3 and -27!

jhannybean · Answer

:)

anonymous · Answer

Thank you!!

jhannybean · Answer

No problem, haha.