LOG5 (-1/X) - LOG5 (-X) = -2
I'm working with log problems and have gotten down to the part where 1/5^2 = 1/x^2 but I either did something wrong or forgot a rule, possibly both :/ not very familiar with them

Question

hartnn · Answer

why do you think thats wrong ?

hartnn · Answer

1/x^2 = 1/5^2
gives

x^2 = 5^2
x =+5 or -5

hartnn · Answer

and x =+5 is not possible,
so its x =-5

anonymous · Answer

Could you please show me the step where you are setting it equal to 0? and therefore get x= +or -5? I tend to forget the basics

hartnn · Answer

oh, this step :
$x^2 = 5^2 \ x^2-5^2 = 0  \ (x+5)(x-5) =0 \ x+5 =0 ~ ~ OR ~~ x-5 =0 \ x= -5, 5$

anonymous · Answer

Yes that step thank you! :)

hartnn · Answer

welcome ^_^