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Chemistry 19 Online
OpenStudy (anonymous):

A car is traveling at a constant velocity of 60 km/h for 4 hours. Choose the correct statement about the acceleration of the car. A) The acceleration of this car is zero. B) The acceleration of this car is positive. C) The acceleration of this car is negative. Eliminate D) The acceleration of this car is 15 m/s

OpenStudy (jfraser):

the words "constant velocity" tell you everything

OpenStudy (anonymous):

I'm bad at this, would it be positive?

OpenStudy (jfraser):

if velocity is constant, does that mean its speed is changing?

OpenStudy (anonymous):

No it would be the same rate ? Sorry i'm trying to understand..

OpenStudy (jfraser):

if velocity is constant, it's not changing. That's what constant means.

OpenStudy (jfraser):

acceleration is DEFINED by\[\frac{\Delta v}{\Delta t}\]

OpenStudy (jfraser):

the CHANGE in velocity over time

OpenStudy (anonymous):

ohh, so if V/T that would be 60 divided by 4 is the acceleration?

OpenStudy (jfraser):

no, it's the CHANGE in velocity that's important. if the velocity isn't changing, then the top of the formula is zero.

OpenStudy (anonymous):

So the acceleration would be 0 too? Thanks for trying to explain it, I don't understand stuff too quick..

OpenStudy (jfraser):

when velocity is constant, acceleration is zero. yes

OpenStudy (anonymous):

Thank you so much!

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