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Find an explicit rule for the nth term of the sequence. 2, -8, 32, -128, ...
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Would the answer be a_n = 2 * (-4)^n or a_n = 2 * (-4)^n-1? I picked the first one but I just want to be sure.
@iGreen
The second one.
Since that's what the formula states.
your sequence is a geometric sequence, with first term=2, and constant=-4, so: \[a _{n}=a _{1}q ^{n-1}=2*(-4)^{n-1}\]
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Thank you @Michele_Laino
Thank you! @sunshine201
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