How do you find the vertical and horizontal asymptotes of (x-3)(x+4) / x2 - 1 ?

Question

solomonzelman · Answer

$\LARGE\color{black}{  \frac{(x-3)(x+4)}{x^2-1}                   }$

solomonzelman · Answer

this is the function, right?

solomonzelman · Answer

You have to find all the values for which the denominator, the  $\large\color{black}{ x^2-1                   }$ is equal to $\large\color{black}{  0   }$ .

thestudygirl · Answer

So they would be -1 and 1?

solomonzelman · Answer

yes.

thestudygirl · Answer

Is that only the vertical asymptote?

solomonzelman · Answer

Yes, they are the only ones: $\large\color{black}{x=1  }$  and  $\large\color{black}{x=-1  }$ .

solomonzelman · Answer

https://www.desmos.com/calculator/figv5h58ty this is what the graph is like:

solomonzelman · Answer

if you have any questions, ask.

thestudygirl · Answer

okay thank you I appreciate the help!

solomonzelman · Answer

Not a problem:

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