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The sum of two consecutive odd integers is at least 76. Find the least possible pair of integers.
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n + n + 1 > 76 n + n + 1 ≥ 76 n + n + 2 > 76 n + n + 2 ≥ 76
will give best reply and fan
1,3,5,7,.. ARE all odd numbers. thus we can deduce that the difference between any two consecutive odd numbers, for instance 3 - 1= 2.. thus the difference between any two odd numbers is 2 \[x + (x+2) \ge 76\]
so its D? the fourth one.
@redred154 im sorry please unblock me
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