Help!
What is the polynomial function of lowest degree with lead coefficient 1 and roots i, –2, and 2?

f(x)=x^3-x^2-4x+4
f(x)=x^4-3x^2-4
f(x)=x^4+3x^2-4
f(x)=x^3+x^2-4x-4

Question

Help!
What is the polynomial function of lowest degree with lead coefficient 1 and roots i, –2, and 2?

f(x)=x^3-x^2-4x+4
f(x)=x^4-3x^2-4
f(x)=x^4+3x^2-4
f(x)=x^3+x^2-4x-4

danjs · Answer

Well , for the first one...

x=2 or x=-2 or x=1

is that i supposed to be a one?

anonymous · Answer

No, it is supposed to be i, the imaginary number

danjs · Answer

well it has 3 roots, so it is a 3rd degree polynomial

anonymous · Answer

so already A or D?

danjs · Answer

The first one has roots, 2 , -2, 1
The Last one has roots 2 , -2 , -1

danjs · Answer

oh i see, i wrote it wrong

danjs · Answer

The second one has the roots: 2, -2, +i , -i

anonymous · Answer

The last one or the second one?

danjs · Answer

1) x=2, -2, 1
2) x= 2, -2, +i, -i
3) x = +1, -1, +2i, -2i
4) x = 2, -2, -1

anonymous · Answer

so b is the correct answer

danjs · Answer

yea