Question

Find the point of intersection between: Pt=(3t-4,2t-1) and 4x+3y=18.

Best answer gets medal!

Answer 1

what do you know about parametric form of line ?

Answer 2

In y=mx+b form it is y=2/3x + 5/3

Answer 3

one approach
start with a sketch of the line
when x = 0 y = 6
when y = 0 x =18/4 = 9/2

Answer 4

Excellent! so you have eliminated the parameter already

you have two equations :
\[y = \frac{2}{3}x + \frac{5}{3}\tag {1}\]
\[4x+3y = 18 \tag{2}\]

solve them using substitution

Answer 5

and 4x + 3y = 18 in y=mx+b is y=-4/3 + 6