Question

Help Again I been having a hard time trying to solve for this!
find the area under one arch of the trochoid: x=6(theta)−4 sin(theta) y=6−4 cos(theta)

Answer 1

@mathmath333

Answer 2

ah okay!

Answer 3

what have you tried so far

Answer 4

ok so I tried:

Because I know A= \[\int\limits_{\alpha}^{\beta}(g(x))(f'(x))
so then:
ok so I tried:

Because I know A= \[\int\limits_{\pi}^{\2pi}(6(theta)-4sin(theta)(-4sin(theta))

Answer 5

yeah I am not sure there