Question

Three times the second of three consecutive even integers is twelve less than twice the sum of the first and third integers. Find the largest even integer

Answer 1

if we called the 3 even integers ( X-2 , X , X+2) because they are consecutive .
three times of the second of three (X) is 3X
is twelve less than ( add this value to make equation) 3X +12
twice the sum of the first and third 2*(X-2+X+2) = 4X
\[4X = 3X +12 \] \[X = 12 \]

the three even integers are { 10, 12,14}