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what value completes the square for the expression? x^2-16x
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@Jhannybean She has a PhD in completing the square
(x-8)^2 this you asking ? x^2 -16x +64
I got the answer -64? is that correct, I also thought it was 32. I have no idea
\[x^2-16x \implies (x-8)^2-64\]
\[\color{red}{x^2-16x}\]\[c=\left(\frac{-16}{2}\right)^2 = (-8)^2 = 64\]\[\implies (x^2 -16x+64)+0\]\[\implies (x-8)^2 +0-64\]\[\implies (x-8)^2-64\]
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