Question

How do I solve 4^x = 1/2 ^x-3
a.5
b.9
c.12
d.1

Answer 1

Hint:
\[\Large 4^{x} = \left(\frac{1}{2}\right)^{x-3}\]
\[\Large (2^2)^{x} = \left(2^{-1}\right)^{x-3}\]
\[\Large 2^{2x} = 2^{-1(x-3)}\]
I'll let you finish up.