Question

write as single trigonometric function: sin(90degrees-theta)/cot(90degrees-theta) PLEASE I KNOW THE ANSWER I JUST NEED SOMEONE TO EXPLAIN IT

Answer 1

\[\sin(x)/\cot(x)=\sin(x)\tan(x)\]

Answer 2

how did you get that?

Answer 3

\[\tan(90-x)=-\tan(x)\]

Answer 4

the even/odd identity

Answer 5

i am sorry i am wrong
\[\sin(90-x)=\cos(x)\]

Answer 6

and \[\tan(90-x)=\cot(x)\]
making this hole thing
\[\cos(x)\cot(x)\]