Question

On July 16, 1882, a massive thunderstorm over Dubuque, Iowa, produced huge hailstones. The diameter of some of the hailstones was 17 in. Ice weighs about 0.033 lb/in3. What is the approximate weight of a 17 in. hailstone
@Directrix

Answer 1

V = 4/3 * π * r³

Diameter = 17 so radius = 17/2 = 8.5

Answer 2

V = 4/3 * π * (8.5)³

Answer 3

think i did it wrong

Answer 4

If the volume is 2572.44 cubic inches, then to get the weight is the next step.

Answer 5

alright

Answer 6

2372.44 * 0.033 =

Answer 7

78.29

Answer 8

Yes, to the nearest tenth that is 78.3 pounds
Check your options.

Answer 9

75,80,85,90

Answer 10

On July 16, 1882, a massive thunderstorm over Dubuque, Iowa, produced huge hailstones. The diameter of some of the hailstones was 17 in. Ice weighs about 0.033 lb/in3. What is the approximate weight of a 17 in. hailstone?
a.
75 lb
c.
85 lb
b.
80 lb
d.
90 lb

Answer 11

did i miss a piece in the original sentence ?

Answer 12

2572.44078 times 0.033 =

Answer 13

84.89 now that I allowed for more digits of pi

Answer 14

That does not seem right.

Answer 15

it was 85

Answer 16

I made the error here: 2372.44 * 0.033 =

I put 23 rather than 25. Sorry.

Answer 17

So, 85

Answer 18

its cool .feel like im talkin to a genius or something ,like a computer

Answer 19

an yes 85

Answer 20

How many more problems remain?

Answer 21

well i have 10 and after that i think its a 25 question test and after that ill have to wait till 5:30 pm and take my final test to get my diploma

Answer 22

I mean how many more problems do you want to do on OpenStudy now?

Answer 23

what do you mean by open study like that i can put on here ?