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Mathematics 7 Online
OpenStudy (swamijatin2):

identify the value of x in the given equation (x/x-a) + (x/x-b)=2

OpenStudy (anonymous):

if you make common denominator for the two fraction you will get the right

OpenStudy (swamijatin2):

can x be common denominator

OpenStudy (anonymous):

(x-a)(x-b) ;

OpenStudy (anonymous):

the common one is the denominator that left you any fractions

OpenStudy (swamijatin2):

x(-a-b)

OpenStudy (anonymous):

no x(-a-b) not equal to (x-a)(x-b)

OpenStudy (anonymous):

to find the common denominator you multiply the denominator of the two fraction

OpenStudy (swamijatin2):

(x-a)(x-b) x^2-ax-bx+ab

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

(x-a)*(x-b) multiply the equation;

OpenStudy (swamijatin2):

(x-a)(x-b) x^2-ax-bx+ab

OpenStudy (anonymous):

you wil get in the left side : x(x-b) + x(x-a)

OpenStudy (anonymous):

the right side :- 2(x-a)(x-b)

OpenStudy (anonymous):

2x^2 -2xa -2xb +2ab

OpenStudy (swamijatin2):

ok i get it

OpenStudy (anonymous):

you can continue ? after that

OpenStudy (swamijatin2):

ys i can

OpenStudy (anonymous):

in the end could you please write the answer

OpenStudy (swamijatin2):

ys

OpenStudy (swamijatin2):

x=2ab/a+b ok this is my answer

OpenStudy (anonymous):

ok .that right

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