The perimeter of a rectangle is 58 meters. The width is 6 less than the length. Which system of equations can you use to find the width of the rectangle?
A. lw= 58
l - 2=6
B. 2(l + w)=58
6 + 2w= 2l
C. 2l + 2w= 58
-l + w= -6
D. 2(l + 2)=58
lw=6

Question

The perimeter of a rectangle is 58 meters. The width is 6 less than the length. Which system of equations can you use to find the width of the rectangle?
A. lw= 58 
    l - 2=6
B. 2(l + w)=58 
    6 + 2w= 2l
C. 2l + 2w= 58 
    -l + w= -6
D. 2(l + 2)=58 
    lw=6

anonymous · Answer

if l is the length and w is the width;
w+6 = l

texaschic101 · Answer

perimeter of rectangle : P = 2L + 2W
P = 58
W = L - 6 .....-L + W = -6

I am going with C